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Discussion » Questions » Science and Technology » What is earth's gravititational force on an object 1000 km from the surface. At the surface it is 10m/sec^2

What is earth's gravititational force on an object 1000 km from the surface. At the surface it is 10m/sec^2

1.   0
2.   30 m/sec^2
3.   Something in between.
4.   There is no such thing as gravity...the earth sucks.
5.   What is gravity?
6.   Who really cares?

Posted - June 27, 2018

Responses


  • 5354
    Gravity grows by the inverse square of the distance,  eg: twice as far away means 1/4th the gravity

    from wiki: "Acceleration due to gravity 1000 km above Earth's surface is 7.3 m/s2"
      June 27, 2018 3:58 PM MDT
    2

  • 14795
    4,6 and 5......I'm not getting drawn in to question like this....:( 
      June 27, 2018 4:42 PM MDT
    2

  • 44373
    Well...you just don't know the gravity of the situation. Perhaps you should weigh on it soon.
      June 27, 2018 7:22 PM MDT
    1

  • 14795
    I have a job holding things at the best of times....:)
      June 28, 2018 2:01 AM MDT
    1

  • 44373
    That's what friends are for.
      June 29, 2018 3:29 PM MDT
    1

  • 14795
    You're the Proff....not the Prop.....hehe 
      June 29, 2018 3:34 PM MDT
    1

  • 44373
      June 29, 2018 3:44 PM MDT
    1

  • 14795
    Sad ,but true :(
      June 29, 2018 4:25 PM MDT
    0

  • 22891
    not sure
      June 27, 2018 5:42 PM MDT
    1

  • 46117
    Tree Fiddy?
      June 27, 2018 5:54 PM MDT
    4

  • 44373
    Nickle ninety eight.
      June 27, 2018 7:23 PM MDT
    1

  • 23185
    (I love those two on South Park!)

     - - at least, it was two people in the episode/s I saw; a married couple. So funny!
    :)
      June 28, 2018 9:39 AM MDT
    1

  • 5453
    I'll go with 3.  Something in between because it's the right answer.  

    My science teacher in high school liked to pull stuff like this.  He would ask a question and include a false statement after the question and then mark it wrong if you got confused by the false statement and didn't answer the question.  Ugh. 


      June 27, 2018 6:29 PM MDT
    1

  • 44373
    I did too...but didn't count it against them. I wanted them to think. This post was edited by Element 99 at July 2, 2018 2:41 PM MDT
      June 27, 2018 7:24 PM MDT
    1

  • 7280
    Well, not sure where the trick part of this question is.

    acceleration at the earth's surface is about 1/3 of what you say it is---but based on the acceleration you list, the answer is about .75 m/s^2.

    So I'll vote for #3 first.


      June 27, 2018 7:17 PM MDT
    3

  • 44373
    Oops...caught me. Stupid mistake, mixing meters and feet. A cookie for you. (answer is incorrect though)
      June 27, 2018 7:28 PM MDT
    1

  • 7280
    Which part of my answer was incorrect?
      June 27, 2018 7:29 PM MDT
    2

  • 44373
    It isn't really incorrect as it is somewhere in between, but the numerical value is not.
      June 28, 2018 7:24 AM MDT
    1

  • 7280
    Remember, I'm solving the problem with the parameters you posted.  And I assumed the earth to have an average diameter.
      June 28, 2018 3:29 PM MDT
    0

  • 5835
    Gravity is not a force. It is an acceleration.
      June 27, 2018 7:33 PM MDT
    1

  • 7280
    Gravity and electromagnetism are just two of the four fundamental forces of nature, specifically two that you can observe every day. 

    (Einstein derived Newton's law of gravity from his own theory of relativity and showed that Newton's ideas were a special case of relativity, specifically one applying to weak gravity and low speeds.)

    The remaining two forces work at the atomic level, which we never feel, despite being made of atoms. The strong force holds the nucleus together. Lastly, the weak force is responsible for radioactive decay, specifically, beta decay where a neutron within the nucleus changes into a proton and an electron, which is ejected from the nucleus.

    Without these fundamental forces, you and all the other matter in the universe would fall apart and float away.
      June 27, 2018 7:49 PM MDT
    2

  • 5391
    Bravo 
      June 27, 2018 8:10 PM MDT
    2

  • 5835
    So what?
      June 28, 2018 3:14 AM MDT
    0

  • 7280
    So unless you are going to explain Einstein's "principle of equivalence" and acknowledge the sophistication of Newton's law and its usefulness in solving this question, I don't see what you have posted as contributing to this discussion.
      June 28, 2018 10:34 PM MDT
    0